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Owlet puzzle #80

Released Wednesday, September 23, 2026 UTC

32768
the answer for puzzle #80

The five clues

  1. A five-digit power of two.
  2. A five-digit power of two whose value is one plus the maximum signed 16-bit integer.
  3. The magnitude of the smallest 16-bit signed integer INT16_MIN.
  4. It equals 2¹⁵.
  5. The number of distinct notes an old MIDI tracker could address per channel — and the range 0..32767 fits in a signed 16-bit integer.

Backstory

32,768 = 2¹⁵. Signed 16-bit integers hold values in [−32,768, 32,767]; the asymmetry comes from two's complement having only one zero. Unsigned 16-bit goes 0 to 65,535 = 2¹⁶ − 1. This range powered the SNES and countless early game consoles.

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